Is it possible to extract the steps needed to produce the final answer? for example. `(a*2)/2` -step1-> `a*(2/2)` -step2-> `a` rule of step1: `(x*y)/z --> x*(y/z)` rule of step2: `x/x --> 1`
Is it possible to extract the steps needed to produce the final answer?
for example.
(a*2)/2-step1->a*(2/2)-step2->arule of step1:
(x*y)/z --> x*(y/z)rule of step2:
x/x --> 1